What is the integral from 0 to 1 of (2x^2) ?

The integral from 0 to 1 of (2x^2) is 2/3

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integral from 0 to 1 of (2x^2)

\int_{0}^{1} (2 x^{2}) d x

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

\int_{0}^{1} 2 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= 2 [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= 2 \cdot \frac{1}{3}

Simplify

= \frac{2}{3}

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What is the integral from 0 to 1 of (2x^2) ?
The integral from 0 to 1 of (2x^2) is 2/3