What is the integral from 0 to 1 of (ln(x)) ?

The integral from 0 to 1 of (ln(x)) is -1

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integral from 0 to 1 of (ln(x))

\int_{0}^{1} (ln (x)) d x

- 1

Solution steps

\int_{0}^{1} ln (x) d x

Apply Integration By Parts

: [x ln (x) - \int 1 d x]_{0}^{1}

= [x ln (x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= [x ln (x) - x]_{0}^{1}

Compute the boundaries:

- 1

= - 1

\int_{- 1}^{1} (3 x - 4) d x

\int_{1}^{4} 6 x^{2} d x

\int_{1}^{4} x e^{- x} d x

\int_{1}^{6} \frac{cos ( x )}{x} d x

\int_{0}^{2} 1 + x d x

What is the integral from 0 to 1 of (ln(x)) ?
The integral from 0 to 1 of (ln(x)) is -1