What is the integral from-2 to 3 of (3x^4-4x^3-x-4) ?

The integral from-2 to 3 of (3x^4-4x^3-x-4) is 155/2

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integral from-2 to 3 of (3x^4-4x^3-x-4)

\int_{- 2}^{3} (3 x^{4} - 4 x^{3} - x - 4) d x

\frac{155}{2}

Decimal

77.5

Solution steps

\int_{- 2}^{3} 3 x^{4} - 4 x^{3} - x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{3} 3 x^{4} d x - \int_{- 2}^{3} 4 x^{3} d x - \int_{- 2}^{3} x d x - \int_{- 2}^{3} 4 d x

\int_{- 2}^{3} 3 x^{4} d x = 165

\int_{- 2}^{3} 4 x^{3} d x = 65

\int_{- 2}^{3} x d x = \frac{5}{2}

\int_{- 2}^{3} 4 d x = 20

= 165 - 65 - \frac{5}{2} - 20

Simplify

165 - 65 - \frac{5}{2} - 20 : \frac{155}{2}

= \frac{155}{2}

\int_{0}^{1} e^{2 x^{3}} d x

\int_{4}^{9} x^{\frac{3}{2}} d x

\int_{0}^{e^{- z^{4}}} z d z

\int_{0}^{x^{2}} t^{\frac{3}{2}} d t

\int_{0}^{4} (2 x + x) d x

What is the integral from-2 to 3 of (3x^4-4x^3-x-4) ?
The integral from-2 to 3 of (3x^4-4x^3-x-4) is 155/2