What is the integral from-3 to 1 of e^{u+3} ?

The integral from-3 to 1 of e^{u+3} is e^4-1

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integral from-3 to 1 of e^{u+3}

\int_{- 3}^{1} e^{u + 3} d u

e^{4} - 1

Decimal

53.59815 \dots

Solution steps

\int_{- 3}^{1} e^{u + 3} d u

e^{u + 3} = e^{3} e^{u}

= \int_{- 3}^{1} e^{3} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{3} \cdot \int_{- 3}^{1} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{3} [e^{u}]_{- 3}^{1}

Compute the boundaries:

e - \frac{1}{e ^{3}}

= e^{3} (e - \frac{1}{e ^{3}})

Simplify

= e^{4} - 1

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What is the integral from-3 to 1 of e^{u+3} ?
The integral from-3 to 1 of e^{u+3} is e^4-1