What is the integral from 2 to 3 of 1/((x-1)^2) ?

The integral from 2 to 3 of 1/((x-1)^2) is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 3 of 1/((x-1)^2)

\int_{2}^{3} \frac{1}{( x - 1 ) ^{2}} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{2}^{3} \frac{1}{( x - 1 ) ^{2}} d x

Apply u-substitution

: \int_{1}^{2} \frac{1}{u ^{2}} d u

= \int_{1}^{2} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{1}^{2}

= [- \frac{1}{u}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\int_{3}^{7} \frac{3}{7 - x} d x

\int_{0}^{1} cos (t) d t

\int_{0}^{3} ∣ 5 x - 9 ∣ d x

\int_{0}^{a} x^{- \frac{4}{3}} d x

\int_{- 1}^{2} x x^{2} - 1 d x

What is the integral from 2 to 3 of 1/((x-1)^2) ?
The integral from 2 to 3 of 1/((x-1)^2) is 1/2