What is the integral from 0 to pi/6 of 8cos(x) ?

The integral from 0 to pi/6 of 8cos(x) is 4

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integral from 0 to pi/6 of 8cos(x)

\int_{0}^{\frac{π}{6}} 8 cos (x) d x

4

Solution steps

\int_{0}^{\frac{π}{6}} 8 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{\frac{π}{6}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 8 [sin (x)]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{2}

= 8 \cdot \frac{1}{2}

Simplify

= 4

\int_{0}^{\frac{π}{2}} (x + 1) sin (x) d x

\int_{0}^{1} 7 x^{5} x^{3} + 8 d x

\int_{0}^{1} 24 x y d y

\int_{1}^{\infty} 4 x^{- 5} d x

\int_{0}^{1} x (x - 1) d x

What is the integral from 0 to pi/6 of 8cos(x) ?
The integral from 0 to pi/6 of 8cos(x) is 4