What is the integral from 1 to 2 of (sqrt(4))/2 ?

The integral from 1 to 2 of (sqrt(4))/2 is 1

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integral from 1 to 2 of (sqrt(4))/2

\int_{1}^{2} \frac{4}{2} d x

1

Solution steps

\int_{1}^{2} \frac{4}{2} d x

Integral of a constant:

\int a d x = a x

= [\frac{4}{2} x]_{1}^{2}

Multiply

\frac{4}{2} x : x

= [x]_{1}^{2}

Compute the boundaries:

1

= 1

\int_{0}^{1} x x + 3 d x

\int_{0}^{4} \frac{3}{16} x d x

\int_{1}^{2} \frac{1}{2 x} d x

\int_{- 1}^{1} (x^{4} - x^{8}) d x

\int_{0}^{4.4} 3 3 x + 4 d x

What is the integral from 1 to 2 of (sqrt(4))/2 ?
The integral from 1 to 2 of (sqrt(4))/2 is 1