What is the integral from 4 to 9 of 1/x ?

The integral from 4 to 9 of 1/x is 2ln(3)-2ln(2)

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integral from 4 to 9 of 1/x

\int_{4}^{9} \frac{1}{x} d x

2 ln (3) - 2 ln (2)

Decimal

0.81093 \dots

Solution steps

\int_{4}^{9} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{4}^{9}

Compute the boundaries:

2 ln (3) - 2 ln (2)

= 2 ln (3) - 2 ln (2)

\int_{0}^{4} (8 x - 32) d x

\int_{3}^{- 3} (3 r + 2)^{2} d r

\int_{0}^{8} (16 x - 128) d x

\int_{0}^{2} x^{3} sin (x) d x

\int_{0}^{3} e^{x^{2}} x d x

What is the integral from 4 to 9 of 1/x ?
The integral from 4 to 9 of 1/x is 2ln(3)-2ln(2)