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Popular >

integral from 0 to 2 of (4x-8)

Solution

\int_{0}^{2} (4 x - 8) d x

Solution

- 8

Solution steps

\int_{0}^{2} 4 x - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 4 x d x - \int_{0}^{2} 8 d x

\int_{0}^{2} 4 x d x = 8

\int_{0}^{2} 8 d x = 16

= 8 - 16

Simplify

= - 8

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (4x-8) ?
The integral from 0 to 2 of (4x-8) is -8