What is the integral from 1 to 3 of 3x^2-12x+9 ?

The integral from 1 to 3 of 3x^2-12x+9 is -4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of 3x^2-12x+9

\int_{1}^{3} 3 x^{2} - 12 x + 9 d x

- 4

Solution steps

\int_{1}^{3} 3 x^{2} - 12 x + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 3 x^{2} d x - \int_{1}^{3} 12 x d x + \int_{1}^{3} 9 d x

\int_{1}^{3} 3 x^{2} d x = 26

\int_{1}^{3} 12 x d x = 48

\int_{1}^{3} 9 d x = 18

= 26 - 48 + 18

Simplify

= - 4

\int_{0}^{\frac{π}{4}} 5 x cos (x^{2}) d x

\int_{2}^{3} (8 t^{3} - 6 t^{- 2}) d t

\int_{0}^{1} 3 + x x d x

\int_{0}^{3} 9 - r^{2} r d r

\int_{1}^{e^{x}} 7 ln (x) d x

What is the integral from 1 to 3 of 3x^2-12x+9 ?
The integral from 1 to 3 of 3x^2-12x+9 is -4