What is the integral from 1 to 3 of \sqrt[3]{x} ?

The integral from 1 to 3 of \sqrt[3]{x} is (9\sqrt[3]{3}-3)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of \sqrt[3]{x}

\int_{1}^{3} 3 x d x

\frac{9 3 3 - 3}{4}

Decimal

2.49506 \dots

Solution steps

\int_{1}^{3} 3 x d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{3}

= [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{3}

Compute the boundaries:

\frac{9 3 3}{4} - \frac{3}{4}

= \frac{9 3 3}{4} - \frac{3}{4}

Simplify

= \frac{9 3 3 - 3}{4}

\int_{1}^{\infty} \frac{1}{2 x ^{2}} d x

\int_{1}^{4} x^{2} - x d x

\int_{0}^{1} \frac{1}{2 - x} d x

\int_{0}^{x} 6 x (1 - x) d x

\int_{0}^{π} θ^{4} + 4 θ^{2} d θ

What is the integral from 1 to 3 of \sqrt[3]{x} ?
The integral from 1 to 3 of \sqrt[3]{x} is (9\sqrt[3]{3}-3)/4