What is the integral from 0 to 16 of sqrt(t) ?

The integral from 0 to 16 of sqrt(t) is 128/3

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integral from 0 to 16 of sqrt(t)

\int_{0}^{16} t d t

\frac{128}{3}

Decimal

42.66666 \dots

Solution steps

\int_{0}^{16} t d t

Apply the Power Rule

: [\frac{2}{3} t^{\frac{3}{2}}]_{0}^{16}

= [\frac{2}{3} t^{\frac{3}{2}}]_{0}^{16}

Compute the boundaries:

\frac{128}{3}

= \frac{128}{3}

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What is the integral from 0 to 16 of sqrt(t) ?
The integral from 0 to 16 of sqrt(t) is 128/3