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Popular >

integral from 0 to 4 of x^2-9

Solution

\int_{0}^{4} x^{2} - 9 d x

Solution

- \frac{44}{3}

+1

Decimal

- 14.66666 \dots

Solution steps

\int_{0}^{4} x^{2} - 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 9 d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 9 d x = 36

= \frac{64}{3} - 36

Simplify

\frac{64}{3} - 36 : - \frac{44}{3}

= - \frac{44}{3}

Graph

Popular Examples

integral from 0 to 1 of sqrt(4x^2+1)x

\int_{0}^{1} 4 x^{2} + 1 x d x

integral from 4 to 5 of 16-x^2

\int_{4}^{5} 16 - x^{2} d x

integral from 0 to 10 of 1/(1+x^2)

\int_{0}^{10} \frac{1}{1 + x ^{2}} d x

integral from 0 to 1 of x^2+x^4

\int_{0}^{1} x^{2} + x^{4} d x

integral from 0 to 1 of-x^2+2

\int_{0}^{1} - x^{2} + 2 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of x^2-9 ?
The integral from 0 to 4 of x^2-9 is -44/3