What is the integral from 4 to 5 of (2x-7)^4 ?

The integral from 4 to 5 of (2x-7)^4 is 121/5

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integral from 4 to 5 of (2x-7)^4

\int_{4}^{5} (2 x - 7)^{4} d x

\frac{121}{5}

Decimal

24.2

Solution steps

\int_{4}^{5} (2 x - 7)^{4} d x

Apply u-substitution

: \int_{1}^{3} \frac{u ^{4}}{2} d u

= \int_{1}^{3} \frac{u ^{4}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{1}^{3} u^{4} d u

Apply the Power Rule

: [\frac{u ^{5}}{5}]_{1}^{3}

= \frac{1}{2} [\frac{u ^{5}}{5}]_{1}^{3}

Compute the boundaries:

\frac{242}{5}

= \frac{1}{2} \cdot \frac{242}{5}

Simplify

= \frac{121}{5}

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What is the integral from 4 to 5 of (2x-7)^4 ?
The integral from 4 to 5 of (2x-7)^4 is 121/5