What is the integral from 0 to 1 of (-x^2-3x) ?

The integral from 0 to 1 of (-x^2-3x) is -11/6

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integral from 0 to 1 of (-x^2-3x)

\int_{0}^{1} (- x^{2} - 3 x) d x

- \frac{11}{6}

Decimal

- 1.83333 \dots

Solution steps

\int_{0}^{1} - x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{1} x^{2} d x - \int_{0}^{1} 3 x d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} 3 x d x = \frac{3}{2}

= - \frac{1}{3} - \frac{3}{2}

Simplify

- \frac{1}{3} - \frac{3}{2} : - \frac{11}{6}

= - \frac{11}{6}

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What is the integral from 0 to 1 of (-x^2-3x) ?
The integral from 0 to 1 of (-x^2-3x) is -11/6