What is the integral from 0 to 9 of sqrt(2t) ?

The integral from 0 to 9 of sqrt(2t) is 18sqrt(2)

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integral from 0 to 9 of sqrt(2t)

\int_{0}^{9} 2 t d t

182

Decimal

25.45584 \dots

Solution steps

\int_{0}^{9} 2 t d t

Apply Integration By Parts

: [2 t t - \int \frac{t}{2} d t]_{0}^{9}

= [2 t t - \int \frac{t}{2} d t]_{0}^{9}

\int \frac{t}{2} d t = \frac{2}{3} t^{\frac{3}{2}}

= [2 t t - \frac{2}{3} t^{\frac{3}{2}}]_{0}^{9}

Compute the boundaries:

182

= 182

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What is the integral from 0 to 9 of sqrt(2t) ?
The integral from 0 to 9 of sqrt(2t) is 18sqrt(2)