What is the integral from 1 to 2 of-4t^{-4} ?

The integral from 1 to 2 of-4t^{-4} is -7/6

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integral from 1 to 2 of-4t^{-4}

\int_{1}^{2} - 4 t^{- 4} d t

- \frac{7}{6}

Decimal

- 1.16666 \dots

Solution steps

\int_{1}^{2} - 4 t^{- 4} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int_{1}^{2} t^{- 4} d t

Apply the Power Rule

: [- \frac{1}{3 t ^{3}}]_{1}^{2}

= - 4 [- \frac{1}{3 t ^{3}}]_{1}^{2}

Compute the boundaries:

\frac{7}{24}

= - 4 \cdot \frac{7}{24}

Simplify

= - \frac{7}{6}

\int_{0}^{2} (x^{4} - 8 x) d x

\int_{- 1}^{2} (2 - x) d x

\int_{- 2}^{2} \frac{x ^{3}}{1 + x ^{2}} d x

\int_{0}^{2} 2 x - 4 d x

\int_{0}^{l n (x)} y e^{z} d z

What is the integral from 1 to 2 of-4t^{-4} ?
The integral from 1 to 2 of-4t^{-4} is -7/6