What is the integral from 0 to pi of sin(u) ?

The integral from 0 to pi of sin(u) is 2

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integral from 0 to pi of sin(u)

\int_{0}^{π} sin (u) d u

2

Solution steps

\int_{0}^{π} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= [- cos (u)]_{0}^{π}

Compute the boundaries:

2

= 2

\int_{\frac{1}{x}}^{x} cos (t^{2}) d t

\int_{2}^{3} (2 t - t^{2}) d t

\int_{2}^{3} - x^{2} + 2 x + 3 d x

\int_{0}^{\infty} \frac{1}{2 x ^{2}} d x

\int_{0}^{\infty} 3 x e^{- 2 x} d x

What is the integral from 0 to pi of sin(u) ?
The integral from 0 to pi of sin(u) is 2