What is the integral from-2 to 2 of (x+|x|)e^{-|x|} ?

The integral from-2 to 2 of (x+|x|)e^{-|x|} is 2(-3/(e^2)+1)

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integral from-2 to 2 of (x+|x|)e^{-|x|}

\int_{- 2}^{2} (x + ∣ x ∣) e^{- ∣ x ∣} d x

2 (- \frac{3}{e ^{2}} + 1)

Decimal

1.18798 \dots

Solution steps

\int_{- 2}^{2} (x + ∣ x ∣) e^{- ∣ x ∣} d x

Eliminate Absolutes

= \int_{- 2}^{0} (x - x) e^{- (- x)} d x + \int_{0}^{2} (x + x) e^{- x} d x

\int_{- 2}^{0} (x - x) e^{- (- x)} d x = 0

\int_{0}^{2} (x + x) e^{- x} d x = 2 (- \frac{3}{e ^{2}} + 1)

= 0 + 2 (- \frac{3}{e ^{2}} + 1)

Simplify

= 2 (- \frac{3}{e ^{2}} + 1)

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What is the integral from-2 to 2 of (x+|x|)e^{-|x|} ?
The integral from-2 to 2 of (x+|x|)e^{-|x|} is 2(-3/(e^2)+1)