What is the integral from-pi to 0 of 0cos(nx) ?

The integral from-pi to 0 of 0cos(nx) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-pi to 0 of 0cos(nx)

\int_{- π}^{0} 0 cos (n x) d x

0

Solution steps

\int_{- π}^{0} 0 \cdot cos (n x) d x

Simplify

= \int_{- π}^{0} 0 d x

Integral of a constant:

\int a d x = a x

= [0 \cdot x]_{- π}^{0}

Simplify

= [0]_{- π}^{0}

Compute the boundaries:

0

= 0

\int_{9}^{16} (x - 2) d x

\int_{0}^{1} \frac{( 1 - x ) ^{3}}{3} d x

\int_{- π}^{x} sin (θ) d θ

\int_{- 1}^{1} x^{99} d x

\int_{0}^{2} x x^{2} + 4 d x

What is the integral from-pi to 0 of 0cos(nx) ?
The integral from-pi to 0 of 0cos(nx) is 0