What is the integral from 0 to 1 of (3x) ?

The integral from 0 to 1 of (3x) is 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (3x)

\int_{0}^{1} (3 x) d x

\frac{3}{2}

Decimal

1.5

Solution steps

\int_{0}^{1} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= 3 [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= 3 \cdot \frac{1}{2}

Simplify

= \frac{3}{2}

\int_{1}^{5} (9 x)^{3} d x

\int_{- 2}^{2} (3 - ∣ x ∣) d x

\int_{1}^{2} \frac{x ^{5} + 7 x ^{2}}{x ^{2}} d x

\int_{π}^{x} \frac{cos ( y )}{y} d y

\int_{- 1}^{1} \frac{5}{3 + x ^{2}} d x

What is the integral from 0 to 1 of (3x) ?
The integral from 0 to 1 of (3x) is 3/2