What is the integral from-1 to 1 of xsqrt(1+x^2) ?

The integral from-1 to 1 of xsqrt(1+x^2) is 0

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integral from-1 to 1 of xsqrt(1+x^2)

\int_{- 1}^{1} x 1 + x^{2} d x

0

Solution steps

\int_{- 1}^{1} x 1 + x^{2} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x 1 + x^{2} :

Odd

= 0

\int_{0}^{π} (x cos (x)) d x

\int_{0}^{1} x^{3} 4 x^{2} + 1 d x

\int_{0}^{5 π} sin (x) d x

\int_{x}^{3} sin (t^{4}) d t

\int_{0}^{2} x^{2} - 2 x + 1 d x

What is the integral from-1 to 1 of xsqrt(1+x^2) ?
The integral from-1 to 1 of xsqrt(1+x^2) is 0