What is the integral from 0 to 5pi of sin(x) ?

The integral from 0 to 5pi of sin(x) is 2

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integral from 0 to 5pi of sin(x)

\int_{0}^{5 π} sin (x) d x

2

Solution steps

\int_{0}^{5 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{5 π}

Compute the boundaries:

2

= 2

\int_{x}^{3} sin (t^{4}) d t

\int_{0}^{2} x^{2} - 2 x + 1 d x

\int_{0}^{π} e^{x} cos (e^{x}) d x

\int_{0}^{19 π} sin (x) d x

\int_{2}^{x y} 24 x y d z

What is the integral from 0 to 5pi of sin(x) ?
The integral from 0 to 5pi of sin(x) is 2