What is the integral from-4 to 0 of sqrt(x+4) ?

The integral from-4 to 0 of sqrt(x+4) is 16/3

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integral from-4 to 0 of sqrt(x+4)

\int_{- 4}^{0} x + 4 d x

\frac{16}{3}

Decimal

5.33333 \dots

Solution steps

\int_{- 4}^{0} x + 4 d x

Apply u-substitution

: \int_{0}^{4} u d u

= \int_{0}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

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What is the integral from-4 to 0 of sqrt(x+4) ?
The integral from-4 to 0 of sqrt(x+4) is 16/3