What is the integral from-5 to 5 of (9piz+(81pi)/2) ?

The integral from-5 to 5 of (9piz+(81pi)/2) is 405pi

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integral from-5 to 5 of (9piz+(81pi)/2)

\int_{- 5}^{5} (9 π z + \frac{81 π}{2}) d z

405 π

Decimal

1272.34502 \dots

Solution steps

\int_{- 5}^{5} 9 π z + \frac{81 π}{2} d z

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{5} 9 π z d z + \int_{- 5}^{5} \frac{81 π}{2} d z

\int_{- 5}^{5} 9 π z d z = 0

\int_{- 5}^{5} \frac{81 π}{2} d z = 405 π

= 0 + 405 π

Simplify

= 405 π

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What is the integral from-5 to 5 of (9piz+(81pi)/2) ?
The integral from-5 to 5 of (9piz+(81pi)/2) is 405pi