What is the derivative of 1/(2y^{3/2)} ?

The derivative of 1/(2y^{3/2)} is -3/(4y^{5/2)}

What is the first derivative of 1/(2y^{3/2)} ?

The first derivative of 1/(2y^{3/2)} is -3/(4y^{5/2)}

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derivative of

\frac{1}{2 y ^{\frac{3}{2}}}

- \frac{3}{4 y ^{\frac{5}{2}}}

Solution steps

\frac{d}{d y} (\frac{1}{2 y ^{\frac{3}{2}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d y} (\frac{1}{y ^{\frac{3}{2}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d y} (y^{- \frac{3}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- \frac{3}{2} y^{- \frac{3}{2} - 1})

Simplify

\frac{1}{2} (- \frac{3}{2} y^{- \frac{3}{2} - 1}) : - \frac{3}{4 y ^{\frac{5}{2}}}

= - \frac{3}{4 y ^{\frac{5}{2}}}

\int_{0}^{1} \frac{1}{4 x - 1} d x

\int \frac{cos ( x )}{cos ( x ) + sin ( x )} d x

\int_{1}^{9} f (x) d x

x \to - 1 lim (arctan (\frac{x - 1}{x + 1}))

6 x^{3}

What is the derivative of 1/(2y^{3/2)} ?
The derivative of 1/(2y^{3/2)} is -3/(4y^{5/2)}
What is the first derivative of 1/(2y^{3/2)} ?
The first derivative of 1/(2y^{3/2)} is -3/(4y^{5/2)}