What is the limit as x approaches-1 of arctan((x-1)/(x+1)) ?

The limit as x approaches-1 of arctan((x-1)/(x+1)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-1 of arctan((x-1)/(x+1))

x \to - 1 lim (arctan (\frac{x - 1}{x + 1}))

diverges

Solution steps

x \to - 1 lim (arctan (\frac{x - 1}{x + 1}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (arctan (\frac{x - 1}{x + 1})) = - \frac{π}{2}

x \to - 1 - lim (arctan (\frac{x - 1}{x + 1})) = \frac{π}{2}

= diverges

6 x^{3}

(5 - 7 x)^{3}

12 (x - \frac{1}{x})^{2}, at x = 2

\frac{d}{d x} (\frac{1 - x ^{2}}{1 + x ^{2}})

\frac{d y}{d x} = - 4 y

What is the limit as x approaches-1 of arctan((x-1)/(x+1)) ?
The limit as x approaches-1 of arctan((x-1)/(x+1)) is diverges