en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 1 of (2x^2+5)

Solution

\int_{- 2}^{1} (2 x^{2} + 5) d x

Solution

21

Solution steps

\int_{- 2}^{1} 2 x^{2} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 2 x^{2} d x + \int_{- 2}^{1} 5 d x

\int_{- 2}^{1} 2 x^{2} d x = 6

\int_{- 2}^{1} 5 d x = 15

= 6 + 15

Simplify

= 21

Graph

Popular Examples

integral from 0 to 2 of (e^x)

\int_{0}^{2} (e^{x}) d x

integral from 0 to 3 of 4x(x-6)

\int_{0}^{3} 4 x (x - 6) d x

integral from 0 to 5 of x-3

\int_{0}^{5} x - 3 d x

integral from 0 to 2 of (6x-9)(8x^2+2)

\int_{0}^{2} (6 x - 9) (8 x^{2} + 2) d x

integral from 0 to 3 of (e^x)/(10+e^x)

\int_{0}^{3} \frac{e ^{x}}{10 + e ^{x}} d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 1 of (2x^2+5) ?
The integral from-2 to 1 of (2x^2+5) is 21