What is the integral from 0 to 9 of x^3 ?

The integral from 0 to 9 of x^3 is 6561/4

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integral from 0 to 9 of x^3

\int_{0}^{9} x^{3} d x

\frac{6561}{4}

Decimal

1640.25

Solution steps

\int_{0}^{9} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{9}

= [\frac{x ^{4}}{4}]_{0}^{9}

Compute the boundaries:

\frac{6561}{4}

= \frac{6561}{4}

\int_{- 1}^{1} x^{\frac{5}{3}} d x

\int_{- 1}^{0} 3 x^{2} d x

\int_{5}^{7} \frac{1}{x} d x

\int_{\frac{π}{6}}^{\frac{π}{4}} sec^{2} (x) d x

\int_{- 5}^{3} - x^{2} - 3 x d x

What is the integral from 0 to 9 of x^3 ?
The integral from 0 to 9 of x^3 is 6561/4