What is the integral from pi/6 to pi/4 of sec^2(x) ?

The integral from pi/6 to pi/4 of sec^2(x) is 1-1/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from pi/6 to pi/4 of sec^2(x)

\int_{\frac{π}{6}}^{\frac{π}{4}} sec^{2} (x) d x

1 - \frac{1}{3}

Decimal

0.42264 \dots

Solution steps

\int_{\frac{π}{6}}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{\frac{π}{6}}^{\frac{π}{4}}

Compute the boundaries:

1 - \frac{1}{3}

= 1 - \frac{1}{3}

\int_{- 5}^{3} - x^{2} - 3 x d x

\int_{1}^{2} \frac{1}{x ^{7}} d x

\int_{0}^{2} x (x - 1) d x

\int_{0}^{\frac{π}{4}} sin^{7} (y) d y

\int_{0}^{1} 17 x e^{x} d x

What is the integral from pi/6 to pi/4 of sec^2(x) ?
The integral from pi/6 to pi/4 of sec^2(x) is 1-1/(sqrt(3))