What is the integral from-2 to 1 of 1/(x^3) ?

The integral from-2 to 1 of 1/(x^3) is diverges

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integral from-2 to 1 of 1/(x^3)

\int_{- 2}^{1} \frac{1}{x ^{3}} d x

diverges

Solution steps

\int_{- 2}^{1} \frac{1}{x ^{3}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} \frac{1}{x ^{3}} d x + \int_{0}^{1} \frac{1}{x ^{3}} d x

\int_{- 2}^{0} \frac{1}{x ^{3}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{0} e^{- x^{2}} d x

\int_{0}^{1} 484 t^{10} + 9 t^{8} d t

\int_{2}^{4} \frac{1}{8} (6 - x - y) d y

\int_{3}^{6} (x^{2} - 9) d x

\int_{0}^{1} \frac{1}{e ^{2 x}} d x

What is the integral from-2 to 1 of 1/(x^3) ?
The integral from-2 to 1 of 1/(x^3) is diverges