What is the integral from 1 to x of (sin(x))/x ?

The integral from 1 to x of (sin(x))/x is \Si(x)-0.9460830704

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integral from 1 to x of (sin(x))/x

\int_{1}^{x} \frac{sin ( x )}{x} d x

Si (x) - 0.9460830704

Solution steps

\int_{1}^{x} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{1}^{x}

Compute the boundaries:

Si (x) - 0.9460830704

= Si (x) - 0.9460830704

\int_{0}^{1} e^{- (x + y)} d x

\int_{0}^{4} \frac{x}{16 + 5 x} d x

\int_{- 4}^{4} e^{x} d x

\int_{0}^{1} (5 x^{e} + 3 e^{x}) d x

\int_{0}^{1} sin (π) x cos (π) x d x

What is the integral from 1 to x of (sin(x))/x ?
The integral from 1 to x of (sin(x))/x is \Si(x)-0.9460830704