What is the integral from 0 to 1 of (5x^e+3e^x) ?

The integral from 0 to 1 of (5x^e+3e^x) is 5/(e+1)+3(e-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (5x^e+3e^x)

\int_{0}^{1} (5 x^{e} + 3 e^{x}) d x

\frac{5}{e + 1} + 3 (e - 1)

Solution steps

\int_{0}^{1} 5 x^{e} + 3 e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 5 x^{e} d x + \int_{0}^{1} 3 e^{x} d x

\int_{0}^{1} 5 x^{e} d x = \frac{5}{e + 1}

\int_{0}^{1} 3 e^{x} d x = 3 (e - 1)

= \frac{5}{e + 1} + 3 (e - 1)

\int_{0}^{1} sin (π) x cos (π) x d x

\int_{t - 2}^{0} (x + 2) d x

\int_{0}^{1} (6 - 9 x^{2}) d x

\int_{0}^{4} (3 x + x) d x

\int_{3}^{7} t^{5} ln (t) d t

What is the integral from 0 to 1 of (5x^e+3e^x) ?
The integral from 0 to 1 of (5x^e+3e^x) is 5/(e+1)+3(e-1)