What is the integral from-4 to 3 of (-x^2-3x) ?

The integral from-4 to 3 of (-x^2-3x) is -119/6

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integral from-4 to 3 of (-x^2-3x)

\int_{- 4}^{3} (- x^{2} - 3 x) d x

- \frac{119}{6}

Solution steps

\int_{- 4}^{3} - x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 4}^{3} x^{2} d x - \int_{- 4}^{3} 3 x d x

\int_{- 4}^{3} x^{2} d x = \frac{91}{3}

\int_{- 4}^{3} 3 x d x = - \frac{21}{2}

= - \frac{91}{3} - (- \frac{21}{2})

Simplify

- \frac{91}{3} - (- \frac{21}{2}) : - \frac{119}{6}

= - \frac{119}{6}

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What is the integral from-4 to 3 of (-x^2-3x) ?
The integral from-4 to 3 of (-x^2-3x) is -119/6