What is the integral from-1 to infinity of 1/(1+x^2) ?

The integral from-1 to infinity of 1/(1+x^2) is (3pi)/4

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integral from-1 to infinity of 1/(1+x^2)

\int_{- 1}^{\infty} \frac{1}{1 + x ^{2}} d x

\frac{3 π}{4}

Solution steps

\int_{- 1}^{\infty} \frac{1}{1 + x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x) + C

Compute the boundaries:

\int_{- 1}^{\infty} \frac{1}{1 + x ^{2}} d x = \frac{π}{2} - (- \frac{π}{4})

= \frac{π}{2} - (- \frac{π}{4})

Simplify

= \frac{3 π}{4}

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What is the integral from-1 to infinity of 1/(1+x^2) ?
The integral from-1 to infinity of 1/(1+x^2) is (3pi)/4