en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (4x-3)

Solution

\int_{0}^{1} (4 x - 3) d x

Solution

- 1

Solution steps

\int_{0}^{1} 4 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x d x - \int_{0}^{1} 3 d x

\int_{0}^{1} 4 x d x = 2

\int_{0}^{1} 3 d x = 3

= 2 - 3

Simplify

= - 1

Popular Examples

integral from 0 to 1 of x/((1+x)^2)

\int_{0}^{1} \frac{x}{( 1 + x ) ^{2}} d x

integral from 1 to 3 of 2/(8+4x)

\int_{1}^{3} \frac{2}{8 + 4 x} d x

integral from 2 to infinity of 1/(x^3-8)

\int_{2}^{\infty} \frac{1}{x ^{3} - 8} d x

integral from-9 to infinity of-4e^{-4x}

\int_{- 9}^{\infty} - 4 e^{- 4 x} d x

integral from 0 to pi/6 of (3cos(x)+1)

\int_{0}^{\frac{π}{6}} (3 cos (x) + 1) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (4x-3) ?
The integral from 0 to 1 of (4x-3) is -1