What is the integral from 0 to pi/6 of (3cos(x)+1) ?

The integral from 0 to pi/6 of (3cos(x)+1) is 3/2+pi/6

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integral from 0 to pi/6 of (3cos(x)+1)

\int_{0}^{\frac{π}{6}} (3 cos (x) + 1) d x

\frac{3}{2} + \frac{π}{6}

Solution steps

\int_{0}^{\frac{π}{6}} 3 cos (x) + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{6}} 3 cos (x) d x + \int_{0}^{\frac{π}{6}} 1 d x

\int_{0}^{\frac{π}{6}} 3 cos (x) d x = \frac{3}{2}

\int_{0}^{\frac{π}{6}} 1 d x = \frac{π}{6}

= \frac{3}{2} + \frac{π}{6}

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What is the integral from 0 to pi/6 of (3cos(x)+1) ?
The integral from 0 to pi/6 of (3cos(x)+1) is 3/2+pi/6