What is the integral from-2pi to 2pi of 8sin(x) ?

The integral from-2pi to 2pi of 8sin(x) is 0

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integral from-2pi to 2pi of 8sin(x)

\int_{- 2 π}^{2 π} 8 sin (x) d x

0

Solution steps

\int_{- 2 π}^{2 π} 8 sin (x) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

8 sin (x) :

Odd

= 0

\int_{π}^{2 π} sin^{2} (θ) d θ

\int_{1}^{3} \frac{x}{4} d x

\int_{0}^{1} x 4 x^{2} + 2 d x

\int_{1}^{0} e^{- x} d x

\int_{\frac{1}{2}}^{1} (x^{- 3} - 4) d x

What is the integral from-2pi to 2pi of 8sin(x) ?
The integral from-2pi to 2pi of 8sin(x) is 0