What is the integral from 0 to 3 of 1/(1+x^2) ?

The integral from 0 to 3 of 1/(1+x^2) is arctan(3)

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integral from 0 to 3 of 1/(1+x^2)

\int_{0}^{3} \frac{1}{1 + x ^{2}} d x

arctan (3)

Solution steps

\int_{0}^{3} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{3}

Compute the boundaries:

arctan (3)

= arctan (3)

\int_{0}^{3} \frac{x}{1 + 5 x ^{2}} d x

\int_{0}^{1} 1 x + 4 d x

\int_{1}^{2} \frac{x ^{3} + 2}{x ^{2}} d x

\int_{2}^{5} (2 x - 3)^{4} d x

\int_{1}^{3} (\frac{1}{x} + \frac{1}{x ^{2}}) d x

What is the integral from 0 to 3 of 1/(1+x^2) ?
The integral from 0 to 3 of 1/(1+x^2) is arctan(3)