What is the integral from 0 to x^3 of sin(x) ?

The integral from 0 to x^3 of sin(x) is -cos(x^3)+1

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integral from 0 to x^3 of sin(x)

\int_{0}^{x^{3}} sin (x) d x

- cos (x^{3}) + 1

Solution steps

\int_{0}^{x^{3}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{x^{3}}

Compute the boundaries:

- cos (x^{3}) + 1

= - cos (x^{3}) + 1

\int_{\frac{1}{e}}^{e} \frac{ln ( x )}{x} d x

\int_{0}^{1} \frac{1}{t} d t

\int_{- \infty}^{1} 0 d x

\int_{0}^{2} \frac{2 t}{1 + t ^{2}} d t

\int_{- 3}^{4} - x^{2} + x + 12 d x

What is the integral from 0 to x^3 of sin(x) ?
The integral from 0 to x^3 of sin(x) is -cos(x^3)+1