What is the integral from 0 to 2pi of e^x ?

The integral from 0 to 2pi of e^x is e^{2pi}-1

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integral from 0 to 2pi of e^x

\int_{0}^{2 π} e^{x} d x

e^{2 π} - 1

Solution steps

\int_{0}^{2 π} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{0}^{2 π}

Compute the boundaries:

e^{2 π} - 1

= e^{2 π} - 1

\int_{1}^{\frac{π}{2}} sin (x) d x

\int_{1}^{3} (x^{2} + 5) d x

\int_{1}^{2} f (2 x) d x

\int_{0}^{4} x (x + 1) d x

\int_{\frac{π}{6}}^{\frac{π}{3}} \frac{1}{sin ( x )} d x

What is the integral from 0 to 2pi of e^x ?
The integral from 0 to 2pi of e^x is e^{2pi}-1