What is the integral from-3 to 0 of sqrt(x+4) ?

The integral from-3 to 0 of sqrt(x+4) is 14/3

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integral from-3 to 0 of sqrt(x+4)

\int_{- 3}^{0} x + 4 d x

\frac{14}{3}

Solution steps

\int_{- 3}^{0} x + 4 d x

Apply u-substitution

: \int_{1}^{4} u d u

= \int_{1}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{4}

Compute the boundaries:

\frac{14}{3}

= \frac{14}{3}

\int_{0}^{y} x e^{y^{3}} d x

\int_{4}^{1} x^{2} d x

\int_{0}^{l n (2)} e^{- 2 y} d y

\int_{- 1}^{3} 6 x^{2} - x^{3} - 8 x d x

\int_{0}^{1} \frac{x}{1 - x} d x

What is the integral from-3 to 0 of sqrt(x+4) ?
The integral from-3 to 0 of sqrt(x+4) is 14/3