What is the integral from 0 to 6-x-z of 1 ?

The integral from 0 to 6-x-z of 1 is 6-x-z

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integral from 0 to 6-x-z of 1

\int_{0}^{6 - x - z} 1 d y

6 - x - z

Solution steps

\int_{0}^{6 - x - z} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{0}^{6 - x - z}

Simplify

= [y]_{0}^{6 - x - z}

Compute the boundaries:

6 - x - z

= 6 - x - z

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What is the integral from 0 to 6-x-z of 1 ?
The integral from 0 to 6-x-z of 1 is 6-x-z