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Popular >

integral from 0 to 4 of (4-2x)

Solution

\int_{0}^{4} (4 - 2 x) d x

Solution

0

Solution steps

\int_{0}^{4} 4 - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 4 d x - \int_{0}^{4} 2 x d x

\int_{0}^{4} 4 d x = 16

\int_{0}^{4} 2 x d x = 16

= 16 - 16

Simplify

= 0

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\int_{1}^{3} \frac{1}{( x + 7 ) ^{2}} d x

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\int_{0}^{π} sin (\frac{x}{2}) cos (n x) d x

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\int_{- 2}^{4} 3 x - 9 d x

integral from 0 to 2 of x^3sqrt(1+x^4)

\int_{0}^{2} x^{3} 1 + x^{4} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (4-2x) ?
The integral from 0 to 4 of (4-2x) is 0