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Popular >

integral from 1 to 2 of (4x^3-6)

Solution

\int_{1}^{2} (4 x^{3} - 6) d x

Solution

9

Solution steps

\int_{1}^{2} 4 x^{3} - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 4 x^{3} d x - \int_{1}^{2} 6 d x

\int_{1}^{2} 4 x^{3} d x = 15

\int_{1}^{2} 6 d x = 6

= 15 - 6

Simplify

= 9

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (4x^3-6) ?
The integral from 1 to 2 of (4x^3-6) is 9