What is the integral from 4 to 6 of x^2+2x-8 ?

The integral from 4 to 6 of x^2+2x-8 is 164/3

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integral from 4 to 6 of x^2+2x-8

\int_{4}^{6} x^{2} + 2 x - 8 d x

\frac{164}{3}

Solution steps

\int_{4}^{6} x^{2} + 2 x - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{6} x^{2} d x + \int_{4}^{6} 2 x d x - \int_{4}^{6} 8 d x

\int_{4}^{6} x^{2} d x = \frac{152}{3}

\int_{4}^{6} 2 x d x = 20

\int_{4}^{6} 8 d x = 16

= \frac{152}{3} + 20 - 16

Simplify

\frac{152}{3} + 20 - 16 : \frac{164}{3}

= \frac{164}{3}

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What is the integral from 4 to 6 of x^2+2x-8 ?
The integral from 4 to 6 of x^2+2x-8 is 164/3