What is the integral from-1 to 5 of cos(x) ?

The integral from-1 to 5 of cos(x) is sin(5)+sin(1)

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integral from-1 to 5 of cos(x)

\int_{- 1}^{5} cos (x) d x

sin (5) + sin (1)

Solution steps

\int_{- 1}^{5} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{- 1}^{5}

Compute the boundaries:

sin (5) + sin (1)

= sin (5) + sin (1)

\int_{- 2}^{- 1} 3 e^{- 5 x + 8} d x

\int_{1}^{3} x^{\frac{3}{4}} d x

\int_{a}^{b} 6 x^{2} d x

\int_{1}^{e} x^{2} \cdot ln (x) d x

\int_{- 2}^{1} 2 y^{2} + 1 d y

What is the integral from-1 to 5 of cos(x) ?
The integral from-1 to 5 of cos(x) is sin(5)+sin(1)