What is the integral from-1 to 2 of 6x ?

The integral from-1 to 2 of 6x is 9

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integral from-1 to 2 of 6x

\int_{- 1}^{2} 6 x d x

9

Solution steps

\int_{- 1}^{2} 6 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{- 1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 1}^{2}

= 6 [\frac{x ^{2}}{2}]_{- 1}^{2}

Compute the boundaries:

\frac{3}{2}

= 6 \cdot \frac{3}{2}

Simplify

= 9

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