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Popular >

integral from 1 to 4 of (x+3)

Solution

\int_{1}^{4} (x + 3) d x

Solution

\frac{33}{2}

+1

Solution steps

\int_{1}^{4} x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x d x + \int_{1}^{4} 3 d x

\int_{1}^{4} x d x = \frac{15}{2}

\int_{1}^{4} 3 d x = 9

= \frac{15}{2} + 9

Simplify

\frac{15}{2} + 9 : \frac{33}{2}

= \frac{33}{2}

Popular Examples

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\int_{- 1}^{5} (3 - ∣ x ∣) d x

integral from 0 to 1 of sqrt(8x+1)

\int_{0}^{1} 8 x + 1 d x

integral from-2 to 1 of x-8|x|

\int_{- 2}^{1} x - 8 ∣ x ∣ d x

integral from 0 to 4 of t^2

\int_{0}^{4} t^{2} d t

integral from 1 to 2 of 1/(x^2-1)

\int_{1}^{2} \frac{1}{x ^{2} - 1} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (x+3) ?
The integral from 1 to 4 of (x+3) is 33/2