What is the integral of 1/(sec(θ)) ?

The integral of 1/(sec(θ)) is sin(θ)+C

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integral of 1/(sec(θ))

\int \frac{1}{sec ( θ )} d θ

sin (θ) + C

Solution steps

\int \frac{1}{sec ( θ )} d θ

Rewrite using trig identities

= \int cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= sin (θ)

Add a constant to the solution

= sin (θ) + C

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